Ha: [address-policy-wg] RE: an arithmetic lesson

>
> > On 3 Dec 2009, at 10:00, <michael.dillon at bt.com> wrote:
> >
> > > an IPv6 /24 and an IPv4 /24 use up the same percentage of the total
> > > address space.
> >
> > How do you work that out? Please enlighten me. 2^24/2^128 x
> > 100 is many orders of magnitude smaller than 2^24/2^32 x 100:
> >    gromit% bc
> >    scale=50
> >    2^24/2^128*100
> >    .00000000000000000000000000000493038065763132378300
> >    2^24/2^32*100
> >    .39062500000000000000000000000000000000000000000000
> >
> > There are of course the same number of IPv4 and IPv6 /24s.
>
> Percentage is calculated by dividing the number of things
> under consideration by the total number of things. When
> I used the word "an", I meant one thing.
>
> Assuming that the number of IPv4 and IPv6 /24s is 10
>
> 1/10 = 1/10
>
> Assuming that the number of IPv4 and IPv6 /24s is 8192
>
> 1/8192 = 1/8192
>
> Assuming that the number of IPv4 and IPv6 /24s is 2882873787
>
> 1/2882873787 = 1/2882873787
>
> Do you see a pattern forming?
>
> --Michael Dillon
>

As I understand:

      IPv4 /24  is  (Total IPv4)/(2^24)
      IPv6 /24  is  (Total IPv6)/(2^24)

Or not ?

WBR,

Dmitry Menzulskiy, DM3740-RIPE
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