<html><body> <tt> > > > On 3 Dec 2009, at 10:00, <michael.dillon@bt.com> wrote: > > > > > an IPv6 /24 and an IPv4 /24 use up the same percentage of the total > > > address space. > > > > How do you work that out? Please enlighten me. 2^24/2^128 x > > 100 is many orders of magnitude smaller than 2^24/2^32 x 100: > > gromit% bc > > scale=50 > > 2^24/2^128*100 > > .00000000000000000000000000000493038065763132378300 > > 2^24/2^32*100 > > .39062500000000000000000000000000000000000000000000 > > > > There are of course the same number of IPv4 and IPv6 /24s. > > Percentage is calculated by dividing the number of things > under consideration by the total number of things. When > I used the word "an", I meant one thing. > > Assuming that the number of IPv4 and IPv6 /24s is 10 > > 1/10 = 1/10 > > Assuming that the number of IPv4 and IPv6 /24s is 8192 > > 1/8192 = 1/8192 > > Assuming that the number of IPv4 and IPv6 /24s is 2882873787 > > 1/2882873787 = 1/2882873787 > > Do you see a pattern forming? > > --Michael Dillon > </tt> As I understand: IPv4 /24 is (Total IPv4)/(2^24) IPv6 /24 is (Total IPv6)/(2^24) Or not ? <tt>WBR,</tt> <tt>Dmitry Menzulskiy, DM3740-RIPE</tt></body></html>